5x^2+20x+32=0

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Solution for 5x^2+20x+32=0 equation:


Simplifying
5x2 + 20x + 32 = 0

Reorder the terms:
32 + 20x + 5x2 = 0

Solving
32 + 20x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
6.4 + 4x + x2 = 0

Move the constant term to the right:

Add '-6.4' to each side of the equation.
6.4 + 4x + -6.4 + x2 = 0 + -6.4

Reorder the terms:
6.4 + -6.4 + 4x + x2 = 0 + -6.4

Combine like terms: 6.4 + -6.4 = 0.0
0.0 + 4x + x2 = 0 + -6.4
4x + x2 = 0 + -6.4

Combine like terms: 0 + -6.4 = -6.4
4x + x2 = -6.4

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -6.4 + 4

Reorder the terms:
4 + 4x + x2 = -6.4 + 4

Combine like terms: -6.4 + 4 = -2.4
4 + 4x + x2 = -2.4

Factor a perfect square on the left side:
(x + 2)(x + 2) = -2.4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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